10=-0.01(x^2)+x

Solution for 10=-0.01(x^2)+x equation:

10=-0.01(x^2)+x

We move all terms to the left:

10-(-0.01(x^2)+x)=0

We get rid of parentheses

0.01x^2-x+10=0

We add all the numbers together, and all the variables

0.01x^2-1x+10=0

a = 0.01; b = -1; c = +10;
Δ = b2-4ac
Δ = -12-4·0.01·10
Δ = 0.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.6}}{2*0.01}=\frac{1-\sqrt{0.6}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.6}}{2*0.01}=\frac{1+\sqrt{0.6}}{0.02}
$